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Lecture 2: Solution of Difference Equations

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Schedule :: Intro :: Inverse :: Properties :: Solution :: Transfer Functions :: System Realization :: Bilateral :: Frequency Response :: Rubber Sheet Geometry :: FIR Filters


\begin{example}Solve
\begin{displaymath}y[k+2] - 5y[k+1] + 6 y[k] = 3f[k+1] +5f[...
...15}(.5)^k - \frac{7}{3}2^k + \frac{18}{5}3^k]u[k]
\end{displaymath}\end{example}

Note that by keeping the portions due to the initial conditions separate from the portions due to the input we can find both the zero-state response and the zero-input response by this method.

Copyright 2008, by the Contributing Authors. Cite/attribute Resource . admin. (2006, May 17). Lecture 2: Solution of Difference Equations. Retrieved January 07, 2011, from Free Online Course Materials — USU OpenCourseWare Web site: http://ocw.usu.edu/Electrical_and_Computer_Engineering/Signals_and_Systems/node4.html. This work is licensed under a Creative Commons License Creative Commons License